[Suggestion] Get another computer's label the same way you get its ID

Question

[Suggestion] Get another computer's label the same way you get its ID

nargyriou opened this issue 7 years ago · 4 comments

nargyriou commented 7 years ago

It's all in the title

It would be pretty cool if you could read another computer's label the same way you can currently read their ID.

Lupus590 · Answer 1 · 2017-07-07T13:07:28.000Z

Or you could implement a way to transmit the label via rednet.

BombBloke · Answer 2 · 2017-07-07T16:16:16.000Z

If you want to find a computer with a specific label, rednet.lookup() can already help you with that.

If you just want a list of all computer labels in the area, that's a different story - although I'm not sure what use such a list would be, if they systems on it are not specifically coded to accept incoming connections from your script anyways.

SquidDev · Answer 3 · 2017-07-07T16:19:57.000Z

I'm presuming this is actually talking about a .getLabel() method on a computer peripheral - which would be a useful feature. Sure, it could be transmitted via rednet, but that isn't a reason to not have it :).

If I'm totally misunderstanding the OP, then ignore me - sorry :).

nargyriou · Answer 4 · 2017-07-07T23:20:23.000Z

Yep, that's what I was suggesting, SquidDev. You got it right. I was getting upset that no one was understanding, thanks for reading carefully. The thing is, to use rednet, you need a modem. You don't need a modem to use computer.getID(), just to be in the adjacent block. Le 7 juil. 2017 18:20, "SquidDev" <[email protected]> a écrit :

…

I'm presuming this is actually talking about a .getLabel() method on a computer peripheral <http://www.computercraft.info/wiki/Computer_%28API%29> - which would be a useful feature. Sure, it could be transmitted via rednet, but that isn't a reason to not have it :). If I'm totally misunderstanding the OP, then ignore me - sorry :). — You are receiving this because you authored the thread. Reply to this email directly, view it on GitHub <#359 (comment)>, or mute the thread <https://github.com/notifications/unsubscribe-auth/AWae4h3bFAjkK6uUPrxUpPZ6TbYmfKMNks5sLlqvgaJpZM4OQ5KE> .

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