Issue description:

The Electric Pump produces extra water.

Steps to reproduce:

1. Build an Electric Pump with no speed or energy upgrade.
2. Charge the pump until it is full and disconnect the energy source.
3. Place water under it until the internal tank is full.
4. Remove the water.

Result
10,000 mB water in the pumps internal tank.
Using 40 RF/t and used 8 kRF.

Energy consumption is 40 RF/t * 20 = 800 RF/s (To get from ticks to seconds)
8000 RF / 800 RF/s = 10s

Water production is 1000 mB/s
1000 mB/s * 10s = 10,000 mB.

Seems right.

5. Place a fluid tank on top of the same pump.
6. Wait until the fluid tank is full.
7. Remove the fluid tank.
8. Place a new fluid tank on top.
9. Place water under the pump

Result
11,000 mB water in the fluid tank
Using 40 RF/t and used 8 kRF.

10. Remove the tank and the water
11. Recharge the pump again and disconnect the energy source.
12. Place a new fluid tank on top.
13. Place water under the pump

Result
21,000 mB water in the fluid tank
Using 40 RF/t and used 16 kRF.

Now im trying an upgrade pump (Full speed and energy). The water is then transferd into an ultimate tank via mechanical pipes and afterwards pulled into an ME-System.

160 kRF are provided.
It uses 400 RF/t.
So 400RF/t * 20 = 8000 RF/s.

160,000 RF / 8,000 RF/s = 20s
With 1000 mB every 2 ticks it produces 10,000 mB/s

10,000 mB/s * 20s = 200,000 mB

I stopped the time and it took 20 seconds to get 201,000 mB of water.
I tried this with 2 and 3 pumps. I got one extra bucket of water for every pump and of course the 200,000 mB water.

Pumps | Water in B
1 | 201
2 | 402
3 | 603

Version

Forge: 12.23.5.2847
Mekanism 1.12.2-9.8.3.390
Other relevant version: MC 1.12.2