
copper cycle (unbalance)
clarkins1 opened this issue ยท 8 comments
Description of the Bug
unbalance
Reproduction
Cu2CH2O5+(H2SO4)2=CO2+(Cu2H2O3)(H2SO4)2
let's assume that here hydrogen peroxide burns and drops out of the process
(Cu2H2O3)(H2SO4)2+(H2O2)(H2O)=(Cu2H2O3)(H2SO4)2
((Cu2H2O3)(H2SO4)2)10+(NaOH)(H2O)=((CuSO4)2(H2O)3)10
in this process the sodium hydroxide solution does not take part and goes to Valhalla
Version
0.1.14.4
Relevant log output
since the process requires 300 mB of sodium hydroxide solution, I will multiply its amount by 10 to use all 1000 mB of sodium hydroxide solution, in this case we will need 3000*10=30000 mB of oxidized malachite leach
and after the manipulations we have done, it turns out that the sodium hydroxide solution does not seem to be involved
here, not the full amount of liquid is used, again I multiply by 10 to balance the income and expenditure part
as a result we see that on the right there are 6 more hydrogen atoms and 3 more oxygen atoms
This can be corrected by changing the amount of water at the outlet from 1300 mB to 1000 mB